10x^2-92x-70=0

Solution for 10x^2-92x-70=0 equation:

10x^2-92x-70=0

a = 10; b = -92; c = -70;
Δ = b2-4ac
Δ = -922-4·10·(-70)
Δ = 11264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11264}=\sqrt{1024*11}=\sqrt{1024}*\sqrt{11}=32\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-32\sqrt{11}}{2*10}=\frac{92-32\sqrt{11}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+32\sqrt{11}}{2*10}=\frac{92+32\sqrt{11}}{20}
$